PostgreSQL JSON类型字段常用操作

作者 : 松哥资源 本文共1919个字,预计阅读时间需要5分钟 发布时间: 2023-01-11 共752人阅读




示例标题

初始数据

insert into name_age values('{"id":1,"name":"小明", "age":18}');
insert into name_age values('{"id":2,"name":"小明1", "age":17}');
insert into name_age values('{"id":3,"name":"小明3", "age":16}');
insert into name_age values('{"id":4,"name":"小明4", "age":20}');
insert into name_age values('{"id":5,"name":"小明5", "age":30}');
insert into name_age values('{"id":6,"name":"小明6", "age":10}');
insert into name_age values('{"id":7,"name":"小明7", "age":15}');
insert into name_age values('{"id":8,"name":"小明8", "age":35}');
insert into name_age values('{"id":9,"name":"小明9", "age":35}');

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Where

精确匹配

SELECT info||'{"gender":"男"}' as a,info||'{"gender":"男"}'::jsonb as b,info as c from name_age where (info->>'id')::int4 = 2;

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SELECT info||'{"gender":"男"}' as a,info||'{"gender":"男"}'::jsonb as b,info as c from name_age where (info->>'name') = '小明4';

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模糊匹配

select * from name_age where info #>> '{name}' like '%明';

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select * from name_age where (info->>'name') like '%4';

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排序

select * from name_age order by info->'age' desc,info->'id' asc;
select * from name_age order by info->>'age' desc,info->'id' asc;
select * from name_age order by info->>'age' desc,info->>'id' asc;

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修改

增加json字段

update name_age set info = info || '{"gender":"男"}'::jsonb  where (info->>'id')::int4 = 1;

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删除json字段

update name_age set info = info-'gender' where  (info->>'id')::int4 = 1;

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修改json字段值

update name_age set info = info || '{"age":16}'::jsonb  where (info->>'id')::int4 = 1;

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分页

select * from name_age order by info->>'age' desc,info->>'id' asc  limit 2 offset 1;
  • offset 从0开始

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其他内容

  1. 统计表占用空间

    SELECT table_schema || '.' || table_name                                         AS table_full_name,
           pg_total_relation_size('"' || table_schema || '"."' || table_name || '"') AS size
    FROM information_schema.tables
    ORDER BY pg_total_relation_size('"' || table_schema || '"."' || table_name || '"') DESC DESC
    
  2. 筛选某个字段包含%的数据

    select * from xxxxx where aaa like '%\%%' ESCAPE '\';
    
    或者 
    
    select * from xxxxx where aaa like '%a%%' ESCAPE 'a';
    


  • 随机毒鸡汤:我已经闲到,开始学习了……


文章来源于justsoso.fun: PostgreSQL JSON类型字段常用操作





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